[issue14894] distutils.LooseVersion fails to compare number and a word

Sam Lai report at bugs.python.org
Thu Sep 12 09:30:51 CEST 2013


Sam Lai added the comment:

I have a more realistic example of this bug. In the docstring for distutils.LooseVersion, it says '1.5.1' and '3.2.p10' are both valid version numbers. If instead of '3.2.p10', we use '1.5.p10', the following occurs -

>>> v1 = LooseVersion('1.5.1')
>>> v2 = LooseVersion('1.5.p10')
>>> v1>v2
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "C:\Python33\Lib\distutils\version.py", line 70, in __gt__
    c = self._cmp(other)
  File "C:\Python33\Lib\distutils\version.py", line 343, in _cmp
    if self.version < other.version:
TypeError: unorderable types: int() < str()
>>> v1.version
[1, 5, 1]
>>> v2.version
[1, 5, 'p', 10]

The reason it occurs is pretty clear when the .version list is printed. (That's also explains why I had to use 1.5.p10 instead because otherwise the comparison would not proceed past the first element of both lists.)

In my real-life example, I'm trying to compare '1.1.0-3' and '1.1.0-beta-10'.

>>> v3=LooseVersion(ll[0])
>>> v4=LooseVersion(ll[1])
>>> v3>v4
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "C:\Python33\Lib\distutils\version.py", line 70, in __gt__
    c = self._cmp(other)
  File "C:\Python33\Lib\distutils\version.py", line 343, in _cmp
    if self.version < other.version:
TypeError: unorderable types: int() < str()
>>> v3.version
[1, 1, 0, '-', 3]
>>> v4.version
[1, 1, 0, '-', 'beta', '-', 10]

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nosy: +samuel.lai

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Python tracker <report at bugs.python.org>
<http://bugs.python.org/issue14894>
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