[issue19272] Can't pickle lambda (while named functions are ok)
Ethan Furman
report at bugs.python.org
Thu Oct 17 04:04:03 CEST 2013
Ethan Furman added the comment:
Jesús Cea Avión added the comment:
>
> If at your "top level" (module) you do:
>
> """
> a = lambda x: 2*x
> """
>
> You don't have an anonymous function, but a function called "a".
Actually, you do have an anonymous function, which happens to be bound to the name "a".
Compare:
--> def a():
... pass
--> a.__name__
'a'
and
--> a = lambda: None
--> a.__name__
'<lambda>'
----------
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<http://bugs.python.org/issue19272>
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