[issue6640] urlparse should parse mailto: URL headers as query parameters

[Volodymyr Bezkostnyy]

Volodymyr Bezkostnyy added the comment:

Tested on 3.4

urllib.parse.urlparse("mailto:foo at example.com?subject=hi")
ParseResult(scheme='mailto', netloc='', path='foo at example.com', params='', query='subject=hi', fragment='')

Work as expected.

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nosy: +asvetlov, webwin

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<http://bugs.python.org/issue6640>
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