[issue14049] execfile() fails on files that use global variables inside functions

[Terry J. Reedy]

Terry J. Reedy <tjreedy at udel.edu> added the comment:

Searching on 'exec NameError' shows that this issue is a duplicate of (behavior issue) #1167300 which contained an essentially identical example"

>>> exec """\
... x = 3
... def f():
...     print x
... f()
... """ in {}, {}

#1167300 was closed as a duplicate of (behavior issue) #991196, which in turn was closed as 'won't fix' (ie, works as it must). Doc issue #4831, which resulted in some doc changes, seems related to this but is not the same. I believe this issue is a duplicate of #13557, which has a patch. I will add my proposed change there.

Anyway, my comments:

In 3.2.2, this runs

#prog='''\
x = 1
def weird():
    y = x + 1
    return y
print(weird())
#'''
#exec(prog)

The same uncommented does also, as does adding ',{}' to the call.
Adding ',{},{}' gives the NameError.
With one named {} arg passed twice, as follows, it runs.

d = {}
exec(prog, d, d)

The reasons for these results are:
1. assignments are *always* to the local namespace.
2. normally, for module code, the local and global namespaces are the same.
3. in the example, 'x=1' is the same as "values['x']=1", while within the function, 'y=x+1' looks up x in gvalues.

This is the same explanation as given in #1167300.

----------
nosy: +terry.reedy
resolution:  -> duplicate
status: open -> closed
superseder:  -> exec of list comprehension fails on NameError
versions: +Python 3.2, Python 3.3

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