[issue14222] Use time.steady() to implement timeout

[Raymond Hettinger]

Raymond Hettinger <raymond.hettinger at gmail.com> added the comment:

I'm closing this one.  The "not subject to adjustment" property is more desirable than not.  The "undefined reference point" property isn't harmful in this context (the start time isn't exposed).  

I'll follow the python-dev thread and re-open this if it becomes clear that there are any issues for steady() being used for timeout logic.

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status: open -> closed

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Python tracker <report at bugs.python.org>
<http://bugs.python.org/issue14222>
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