[issue11986] Min/max not symmetric in presence of NaN

[Mark Dickinson]

Mark Dickinson <dickinsm at gmail.com> added the comment:

> keep naive implementation of builtin max()

Agreed.

> provide symmetric float.max such that nan.max(x) = x.max(nan) = x (nan
> result would be a valid but less useful alternative.)

That might be viable (a math module function might also make sense here), though it feels a bit YAGNI to me.  If we were going to add such a method, it should follow IEEE 754:  nan.max(x) == x.max(n) == x, but also nan.min(x) == x.min(nan) == x, for finite x.  (See section 5.3.1.)

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