[issue13592] repr(regex) doesn't include actual regex

[Ezio Melotti]

Ezio Melotti <ezio.melotti at gmail.com> added the comment:

If an eval-able re.Regex is used, the flags can be showed as second arg, like:
  re.Regex('a', re.I|re.S)
instead of being added to the pattern as in
  re.Regex('(?is)a')

The repr can be generated with something like
  're.Regex({r.pattern!r}, {r.flags})'.format(r=r)
that currently prints
  re.Regex('abc', 50)
but if #11957 is fixed, the result will look like
  re.Regex('abc', re.I|re.S)
for a regex created with
  r = re.compile('abc', re.I|re.S)

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Python tracker <report at bugs.python.org>
<http://bugs.python.org/issue13592>
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