[issue12772] fractional day attribute in datetime class

[Alexander Belopolsky]

Alexander Belopolsky <alexander.belopolsky at gmail.com> added the comment:

You can easily get the fractional day value using existing functionality:


>>> from datetime import *
>>> (datetime(2011,8,15,18,30) -  datetime(2011,8,13,12,0)) / timedelta(1)
2.2708333333333335
>>> (datetime(2011,8,15,18,30) -  datetime(1970,1,1)) / timedelta(1)
15201.770833333334

In some sense this request is a duplicate of issue2736.

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assignee:  -> belopolsky
nosy: +belopolsky
resolution:  -> rejected
stage:  -> committed/rejected
status: open -> pending

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Python tracker <report at bugs.python.org>
<http://bugs.python.org/issue12772>
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