[issue1289118] timedelta multiply and divide by floating point

[Daniel Stutzbach]

Daniel Stutzbach <daniel at stutzbachenterprises.com> added the comment:

I don't have a strong feeling about the method of rounding.  My thinking is: If my application is sensitive to how the last microsecond is rounded, then I shouldn't be using a type that only gives me 1-microsecond precision.

(Likewise, if my application is sensitive to how the last binary digital of the floating point mantissa is rounded ... I'm in trouble)

That said, round-to-nearest strikes me as the least-surprising approach.

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<http://bugs.python.org/issue1289118>
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