[issue9218] pop multiple elements of a list at once

[Diego Jacobi]

New submission from Diego Jacobi <jacobidiego at gmail.com>:

I am currently working with buffer in an USB device and pyusb.
So when i read from a buffer endpoint i get an array.Array() list.
I handle this chunk of data with a thread to send a receive the information that i need. In this thread i load a list with all the information that is read from the USB device, and another layer with pop this information from the threads buffer.

The thing i found is that, to pop a variable chunk of data from this buffer without copying it and deleting the elements, i have to pop one element at the time.

    def get_chunk(self, size):
        for x in range(size):
            yield self.recv_buffer.pop()

I guess that it would be improved if i can just pop a defined number of elements, like this:

pop self.recv_buffer[:size]
or
self.recv_buffer.pop(,-size)

That would be... "pop from the last element minus size to the last element"
in that way there is only one memory transaction.
The new list points to the old memory address and the recv_buffer is advanced to a new address. Data is not moved.

note that i like the idea of using "pop" as the "del" operator for lists

thanks.
Diego

----------
messages: 109912
nosy: jacobidiego
priority: normal
severity: normal
status: open
title: pop multiple elements of a list at once
type: performance
versions: Python 2.6

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Python tracker <report at bugs.python.org>
<http://bugs.python.org/issue9218>
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