[issue5048] Extending itertools.combinations
Mark Dickinson
report at bugs.python.org
Sun Jan 25 14:08:37 CET 2009
Mark Dickinson <dickinsm at gmail.com> added the comment:
> that dropping the length argument will make the function iterate over
> *all* combinations,
Now *this* sounds more useful to me: an itertool that generates *all* subsets of a list. It's
quite easy to do with existing itertools, though, either by looping over the second argument to
combinations, or (for a different ordering) using product:
def subsets(iterable):
l = list(iterable)
for selector in itertools.product([False, True], repeat=len(l)):
yield [element for indicator, element in zip(selector, l) if indicator]
_______________________________________
Python tracker <report at bugs.python.org>
<http://bugs.python.org/issue5048>
_______________________________________
More information about the Python-bugs-list
mailing list