[ python-Bugs-1153226 ] string interpolation breaks with %d and large float

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Bugs item #1153226, was opened at 2005-02-28 15:10
Message generated for change (Comment added) made by jerub
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https://sourceforge.net/tracker/?func=detail&atid=105470&aid=1153226&group_id=5470

Category: Python Interpreter Core
Group: None
Status: Open
Resolution: None
Priority: 5
Submitted By: Stephen Thorne (jerub)
Assigned to: Nobody/Anonymous (nobody)
Summary: string interpolation breaks with %d and large float

Initial Comment:
We have experienced a problem recently when wanting to
render a large float as a string. Converting the float
to an int/long manuall was required. 

'%d' % f
throws an exception for all floats f, f >= 2**31

Expected output, shown with 'int()' and 'long()':
>>> '%d %d' % (long(float(2**31)), int(float(2**31)))
'2147483648 2147483648'

Non-Working Example.
>>> '%d' % float(2**31)
Traceback (most recent call last):
  File "<stdin>", line 1, in ?
TypeError: int argument required

Tested on:
Python 2.3.4 (#1, Oct 26 2004, 16:42:40) 
Python 2.4.1a0 (#2, Feb  9 2005, 22:42:24)

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>Comment By: Stephen Thorne (jerub)
Date: 2005-03-01 23:21

Message:
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user_id=100823

My immediate reaction is, yes. This is a bug. 

Either floats should work with %d, or they should not at
all. Having a platform dependant upper bound on the size of
the float allowed is a bug.

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Comment By: Josiah Carlson (josiahcarlson)
Date: 2005-03-01 16:36

Message:
Logged In: YES 
user_id=341410

Note that it will also raise a TypeError when the float f, f
< -2**31

Is this a bug?  I don't know.  I tend to not pass floats
when string interpolation is expecting integers.  Maybe the
documentation should be cleared up.

If you really want a truncated float, perhaps "%.0f" is the
format you are looking for, to save you the effort of using
int() or long().

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