[ python-Bugs-1058059 ] Can't read some http URLs using neither urllib, nor urllib2

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Mon Nov 1 14:37:02 CET 2004


Bugs item #1058059, was opened at 2004-11-01 11:47
Message generated for change (Comment added) made by doerwalter
You can respond by visiting: 
https://sourceforge.net/tracker/?func=detail&atid=105470&aid=1058059&group_id=5470

Category: Python Library
Group: Python 2.3
Status: Open
Resolution: None
Priority: 5
Submitted By: Vsevolod Novikov (nnseva)
Assigned to: Nobody/Anonymous (nobody)
Summary: Can't read some http URLs using neither urllib, nor urllib2

Initial Comment:
HTTP connection maden by urllib, as well as by urllib2,
on some URL sleeps forever (until timeout happens) on
reading from the socket.
The popular Linux 'wget' utility behaviour is the same.
The Mozilla browser, as well as Internet Explorer
browser read this URL successfully, over proxy, as well
as directly.
The example URL is:

http://nds.nokia.com/uaprof/N3510ir100.xml

The example code is:

import urllib2
u =
urllib2.urlopen('http://nds.nokia.com/uaprof/N3510ir100.xml')
print u.info()
print '-------------'
for l in u :
    print l
The urllib library does the same.

Info list was (on the moment when I tried it last time):
Accept-Ranges: bytes
Date: Mon, 01 Nov 2004 10:29:58 GMT
Content-Length: 9710
Content-Type: text/plain
Cache-Control: no-cache
Server: Netscape-Enterprise/4.1
X-WR-FLAGS: CCHOMode=7200:0:force
Etag: "acbd4f76-6-25ee-40910c98"
Last-modified: Thu, 29 Apr 2004 14:09:28 GMT
Via: 1.1 saec-nokp02ca (NetCache NetApp/5.3.1R2)

I have no idea why it happens. May be, the HTTP server
waits some additional headers? In any case, it is not a
good behaviour of the library, I think.


----------------------------------------------------------------------

>Comment By: Walter Dörwald (doerwalter)
Date: 2004-11-01 14:37

Message:
Logged In: YES 
user_id=89016

Work here without any problems:
Python 2.3.4 (#2, Sep 29 2004, 18:56:11) 
[GCC 2.96 20000731 (Red Hat Linux 7.3 2.96-113)] on linux2
Type "help", "copyright", "credits" or "license" for more 
information.
>>> import urllib
>>> d = urllib.urlopen
("http://nds.nokia.com/uaprof/N3510ir100.xml").read()
>>> len(d)
9710
>>> d[:30] 
'<?xml version="1.0"?>\n<!-- ==='

----------------------------------------------------------------------

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