[Python-bugs-list] [ python-Bugs-649974 ] urllib.url2pathname('file://host/')...
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Sat, 07 Dec 2002 01:22:07 -0800
Bugs item #649974, was opened at 2002-12-07 02:22
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Category: Python Library
Group: Python 2.2.1
Status: Open
Resolution: None
Priority: 5
Submitted By: Mike Brown (mike_j_brown)
Assigned to: Nobody/Anonymous (nobody)
Summary: urllib.url2pathname('file://host/')...
Initial Comment:
The Unix version of urllib.url2pathname(), when given a
file URL that contains a host part, returns a path with
the host embedded in the URL, despite the fact that
there is no convention for mapping the host into the
URL. The resulting path is not usable.
For example, on Windows, there is a convention for
mapping the host part of a URL to and from a NetBIOS
name. url2pathname('//somehost/path/to/file') returns
r'\somehost\path\to\file' which is safe to pass into open
() or os.access().
But on Unix, there is no such convention. url2pathname
('//somehost/path/to/file') returns '//somehost/path/to/file',
which means the same thing as '/somehost/path/to/file' --
somehost is just another path segment and does not
actually designate a host.
In my opinion, an exception should be raised in this
situation; url2pathname() should not try to produce an
OS path for a remote machine when there is no
convention for referencing a remote machine in that OS's
traditional path format. This way, if no exception is
raised, you know that it's safe to pass the result into
open() or os.access().
And as noted in other bug reports, 'file://localhost/' is a
special case that should be treated the same as 'file:///'.
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https://sourceforge.net/tracker/?func=detail&atid=105470&aid=649974&group_id=5470