[Python-3000] python3000 udp problem

[Nick Coghlan]

Long Ge wrote:
> import socket
> 
> if __name__ == '__main__':
>     print("main")
>     udp = socket.socket(socket.AF_INET,socket.SOCK_DGRAM)
>     udp.sendto("1",0,('127.0.0.1 <http://127.0.0.1>',3722))
>     udp.close()
> 
>  
> *output:*
> main
> Traceback (most recent call last):
>   File "C:\Python30\Projects\udp.py", line 6, in <module>
>     udp.sendto("1",0,('127.0.0.1 <http://127.0.0.1>',3722))
> TypeError: sendto() argument 1 must be bytes or read-only buffer, not str
>  
> what is the problem about argument 1?

Python 3.0 is much stricter than 2.x about the distinction between 
character based-data (i.e. Unicode strings) and 8-bit byte sequences 
(bytes and bytearray).

As Benjamin pointed out, socket.sendto expects a bytestream rather than 
a character string, so you need to either use bytes directly (such as 
b"1") or encode the character string to a byte sequence (such as 
"1".encode("utf-8")).

Cheers,
Nick.

-- 
Nick Coghlan   |   ncoghlan at gmail.com   |   Brisbane, Australia
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