[Python-3000] Stars

[Thomas Wouters]

On 3/1/07, Raymond Hettinger <raymond.hettinger at verizon.net> wrote:
>
> What we have now:
>     def f(a, b, *args, **dict(c=1)):     # Yuck!
>
> What we really need:
>     def f(a, b, *args, **, c=1):           # Two stars spell dictionary.
>
> What I heard was planned instead:
>     def f(a, b, *args, *, c=1):             # One star spells iterable.


Nope. You can only have one one-star and one two-star. If you want
keyword-only arguments *and* arbitrary positional arguments, you can just do
it (in Py3k, and it will probably be backported to 2.6.)

 >>> def foo(a, b, *args, c=1): return a, b, args, c
...
>>> foo(1, 2)
(1, 2, (), 1)
>>> foo(1, 2, 3, 4, c=5)
(1, 2, (3, 4), 5)

The one-star-only syntax is only if you *don't* want arbitrary positional
arguments:

>>> def foo(a, b, *, c=1): return a, b, c
...
>>> foo(1, 2)
(1, 2, 1)
>>> foo(1, 2, 5)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: foo() takes exactly 2 positional arguments (3 given)
>>> foo(1, 2, c=5)
(1, 2, 5)

-- 
Thomas Wouters <thomas at python.org>

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