[Numpy-svn] r5806 - trunk/numpy/core
numpy-svn at scipy.org
numpy-svn at scipy.org
Fri Sep 12 22:53:56 EDT 2008
Author: alan.mcintyre
Date: 2008-09-12 21:53:53 -0500 (Fri, 12 Sep 2008)
New Revision: 5806
Modified:
trunk/numpy/core/fromnumeric.py
trunk/numpy/core/numeric.py
Log:
Fix failing doctests.
Modified: trunk/numpy/core/fromnumeric.py
===================================================================
--- trunk/numpy/core/fromnumeric.py 2008-09-12 19:23:20 UTC (rev 5805)
+++ trunk/numpy/core/fromnumeric.py 2008-09-13 02:53:53 UTC (rev 5806)
@@ -1617,12 +1617,14 @@
>>> x = np.array([1, 2, 3], dtype=np.uint8)
>>> np.prod(x).dtype == np.uint
+ True
If `x` is of a signed integer type, then the output type
is the default platform integer:
>>> x = np.array([1, 2, 3], dtype=np.int8)
>>> np.prod(x).dtype == np.int
+ True
"""
try:
Modified: trunk/numpy/core/numeric.py
===================================================================
--- trunk/numpy/core/numeric.py 2008-09-12 19:23:20 UTC (rev 5805)
+++ trunk/numpy/core/numeric.py 2008-09-13 02:53:53 UTC (rev 5806)
@@ -765,7 +765,7 @@
>>> b = np.arange(24.).reshape(4,3,2)
>>> c = np.tensordot(a,b, axes=([1,0],[0,1]))
>>> c.shape
- (5,2)
+ (5, 2)
>>> c
array([[ 4400., 4730.],
[ 4532., 4874.],
@@ -774,7 +774,7 @@
[ 4928., 5306.]])
>>> # A slower but equivalent way of computing the same...
- >>> c = zeros((5,2))
+ >>> c = np.zeros((5,2))
>>> for i in range(5):
... for j in range(2):
... for k in range(3):
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