[Numpy-discussion] Numpy where

[Benjamin Root]

I think the question is if scalars should be acceptable for the first
argument, not if it should be for the 2nd and 3rd argument.

If scalar can be given for the first argument, the the first three makes
sense. Although, I have no clue why we would allow that.

Ben Root
On Mar 12, 2015 9:25 PM, "Nathaniel Smith" <njs at pobox.com> wrote:

> On Mar 12, 2015 5:02 PM, "Charles R Harris" <charlesr.harris at gmail.com>
> wrote:
> >
> > Hi All,
> >
> > This is apropos gh-5582 dealing with some corner cases of np.where. The
> following are the current behavior
> >
> > >>> import numpy
> > >>> numpy.where(True)  # case 1
> > ... (array([0]),)
> > >>> numpy.where(True, None, None)  # case 2
> > ... array(None, dtype=object)
> > >>> numpy.ma.where(True)  # case 3
> > ... (array([0]),)
> > >>> numpy.ma.where(True, None, None)  # case 4
> > ... (array([0]),)
> >
> > The question is, what exactly should be done in these cases? I'd be
> inclined to raise an error for cases 1 and 3. Case two looks correct to me
> if we agree that scalar inputs are acceptable. Case 4 looks wrong.
>
> I can't think of any reason scalars wouldn't be acceptable. So everything
> you suggest sounds right to me.
>
> -n
> Hi All,
>
> This is apropos gh-5582 <https://github.com/numpy/numpy/pull/5582>
> dealing with some corner cases of np.where. The following are the current
> behavior
>
> >>> import numpy
> >>> numpy.where(True)  # case 1
> ... (array([0]),)
> >>> numpy.where(True, None, None)  # case 2
> ... array(None, dtype=object)
> >>> numpy.ma.where(True)  # case 3
> ... (array([0]),)
> >>> numpy.ma.where(True, None, None)  # case 4
> ... (array([0]),)
>
> The question is, what exactly should be done in these cases? I'd be
> inclined to raise an error for cases 1 and 3. Case two looks correct to me
> if we agree that scalar inputs are acceptable. Case 4 looks wrong.
>
> Thoughts?
>
> Chuck
>
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