[Numpy-discussion] Round away from zero (towards +/- infinity)

[T J]

It does, but it is not portable. That's why I was hoping NumPy might think
about supporting more rounding algorithms.

On Thu, Oct 2, 2014 at 10:00 PM, John Zwinck <jzwinck at gmail.com> wrote:

> On 3 Oct 2014 07:09, "T J" <tjhnson at gmail.com> wrote:
> >
> > Any bites on this?
> >
> > On Wed, Sep 24, 2014 at 12:23 PM, T J <tjhnson at gmail.com> wrote:
> >> Python's round function goes away from zero, so I am looking for the
> NumPy equivalent (and using vectorize() seems undesirable). In this sense,
> it seems that having a ufunc for this type of rounding could be helpful.
> >>
> >> Aside: Is there interest in a more general around() that allows users
> to specify alternative tie-breaking rules, with the default staying 'round
> half to nearest even'? [1]
> >> ---
> >> [1]
> http://stackoverflow.com/questions/16000574/tie-breaking-of-round-with-numpy
>
> I like the solution given in that Stack Overflow post, namely using ctypes
> to call fesetround(). Does that work for you?
>
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