[Numpy-discussion] all elements equal

[Zachary Pincus]

How about the following?
exact: numpy.all(a == a[0])
inexact: numpy.allclose(a, a[0])

On Mar 5, 2012, at 2:19 PM, Keith Goodman wrote:

> On Mon, Mar 5, 2012 at 11:14 AM, Neal Becker <ndbecker2 at gmail.com> wrote:
>> What is a simple, efficient way to determine if all elements in an array (in my
>> case, 1D) are equal?  How about close?
> 
> For the exactly equal case, how about:
> 
> I[1] a = np.array([1,1,1,1])
> I[2] np.unique(a).size
> O[2] 1    # All equal
> 
> I[3] a = np.array([1,1,1,2])
> I[4] np.unique(a).size
> O[4] 2   # All not equal
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