[Numpy-discussion] Fastest distance matrix calc

[Christopher Barker]

Matthieu Brucher wrote:
>     you can probably use numpy.hypot(v-y) to speed this up more...
> 
> 
> Tried it today, hypot takes two arguments :(
> Is there a function that does the square root of the sum of squares ?

then maybe you want:

numpy.hypot(v-y,v-y), though you should probably make a temporary v-y, 
so you dont' make two of them.

I've been assuming that hypot is written in C, rather than just a 
convenience function, but it it's the later, then it won't help here.

-Chris





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