x.min() depends on ordering
Keith Goodman
kwgoodman at gmail.com
Sat Nov 11 18:04:29 EST 2006
x.min() and x.max() depend on the ordering of the elements:
>> x = M.matrix([[ M.nan, 2.0, 1.0]])
>> x.min()
nan
>> x = M.matrix([[ 1.0, 2.0, M.nan]])
>> x.min()
1.0
If I were to try the latter in ipython, I'd assume, great, min()
ignores NaNs. But then the former would be a bug in my program.
Is this related to how sort works?
>> x = M.matrix([[ M.nan, 2.0, 1.0]])
>> x.sort()
>> x
matrix([[ nan, 1. , 2. ]])
>> x = M.matrix([[ 1.0, 2.0, M.nan]])
>> x.sort()
>> x
matrix([[ 1. , 2. , nan]])
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