[New-bugs-announce] [issue30926] KeyError with cgitb inspecting exception in generator expression

Jason R. Coombs report at bugs.python.org
Thu Jul 13 16:46:43 EDT 2017


New submission from Jason R. Coombs:

Consider this script, which runs successfully on Python 3:

import cgitb
import sys


def fiter():
    assert False
    yield 1, 1
    yield 2, 2
    yield 3, 3


try:
    x = set(id_ for id_, _ in fiter())
except:
    print cgitb.html(sys.exc_info())


Run the same script on Python 2.7.13 and you get this error:

Traceback (most recent call last):
  File "test.py", line 15, in <module>
    print(cgitb.html(sys.exc_info()))
  File ".../cgitb.py", line 130, in html
    formatvalue=lambda value: '=' + pydoc.html.repr(value))
  File ".../inspect.py", line 887, in formatargvalues
    specs.append(strseq(args[i], convert, join))
  File ".../inspect.py", line 840, in strseq
    return join(map(lambda o, c=convert, j=join: strseq(o, c, j), object))
  File ".../inspect.py", line 840, in <lambda>
    return join(map(lambda o, c=convert, j=join: strseq(o, c, j), object))
  File ".../inspect.py", line 842, in strseq
    return convert(object)
  File ".../inspect.py", line 884, in convert
    return formatarg(name) + formatvalue(locals[name])
KeyError: 'id_'


Wrap the generator expression in [] and it also succeeds.

Given that the issue only exists on Python 2.7, it may not need to be addressed, but I wanted to log the issue nonetheless.

----------
components: Interpreter Core, Library (Lib)
messages: 298314
nosy: jason.coombs
priority: normal
severity: normal
status: open
title: KeyError with cgitb inspecting exception in generator expression
versions: Python 2.7

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Python tracker <report at bugs.python.org>
<http://bugs.python.org/issue30926>
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