[New-bugs-announce] [issue15813] Python function decorator scope losing variable

[V.E.O]

New submission from V.E.O:

I just learned python @ decorator, it's cool, but soon I found my modified code coming out weird problems.

def with_wrapper(param1):
    def dummy_wrapper(fn):
        print param1
        param1 = 'new'
        fn(param1)
    return dummy_wrapper

def dummy():
    @with_wrapper('param1')
    def implementation(param2):
        print param2

dummy()



I debug it, it throws out exception at print param1

UnboundLocalError: local variable 'param1' referenced before assignment

If I remove param1 = 'new' this line, without any modify operation(link to new object) on variables from outer scope, this routine might working.

Is it meaning I only have made one copy of outer scope variables, then make modification?
The policy of variable scope towards decorator is different?

----------
components: Interpreter Core
messages: 169389
nosy: V.E.O
priority: normal
severity: normal
status: open
title: Python function decorator scope losing variable
type: compile error
versions: Python 2.7

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Python tracker <report at bugs.python.org>
<http://bugs.python.org/issue15813>
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