[Mailman-Users] list subscription spammers

[Will Yardley]

ps - Here are a couple of quick throwaway 'withlist' scripts I threw
together to add a regexp matching the spammers' email addresses, and to
purge pending subscription requests matching a similar regexp. Posting
here in case someone finds them useful for this, or some other, purpose.

% cat purge_requests.py 
# quick "withlist" script.
# call via withlist -r purge_requests LISTNAME
# or via loop:
# for LIST in `./list_lists -b` ; do ./withlist -r purge_requests $LIST ; done

import re
from Mailman import mm_cfg
from Mailman.mm_cfg import DISCARD

email_re = re.compile('^(foo|bar.baz|blah)\+[0-9]+ at example\.com')

def purge_requests(m):
    print "** Checking %s" % m.internal_name()
    m.Lock()
    for item in m.GetSubscriptionIds():
        email_addr = m.GetRecord(item)[1]
        if email_re.match(email_addr):
            print ">> Discarding %s from %s" % (email_addr,
                                                m.internal_name())
            m.HandleRequest(item, DISCARD)
    m.Save()
    m.Unlock()

% cat set_banlist.py 
# quick "withlist" script.
# call via withlist -r set_banlist LISTNAME
# or via loop:
# for LIST in `./list_lists -b` ; do ./withlist -r set_banlist $LIST ; done

# Obviously, the problem becomes a bit more complex if we want to adjust
# the existing rule, vs. adding a new one; then we'd have to track the
# item # within the list, and modify that item (this also shouldn't be
# too hard).

from Mailman import mm_cfg

# This will append the item below to the ban_list for $LISTNAME
# Note additional pattern below; that's just a check to see if the
# pattern already exists.
ban_item = '^(foo|bar.baz|blah)\\+[0-9]+ at example\.com'

def set_banlist(m):
    # Rather than use regex, use this to see if substring is in list
    if not rule_exists(m.ban_list):
	print "**** Updating %s" % m.internal_name()
        m.Lock()
        m.ban_list.append(ban_item)
        m.Save()


# Could probably do this a little more tersely with 'lambda'
def rule_exists(list):
    for item in list:
        if '\(foo' in item:
            return 1