[Mailman-Users] User Commands

[Mark Sapiro]

Karl O. Pinc wrote:
>
>On 02/10/2009 02:07:23 PM, Karl O. Pinc wrote:
>> 
>> On 02/10/2009 10:20:51 AM, Brian Canty wrote:
>>> I was wondering if anyone knows of any command you can use to find  
>>> out
>>> who is subscribed to all mailman lists.
>
>Somehow the "cut" command got mangled.  Should be:
>
>  list_lists \
>   | tail -n +2 \
>   | awk '{print $1;}' \
>   | xargs -n 1 bash -c 'list_members $0 | xargs -n 1 echo $0:' \
>   | grep foo at example.com \
>   | cut -d : -f 1
>
>> Gets you all the lists that foo at example.com is subscribed to.


So does 

  bin/find_member foo at example.com

and much more simply.

-- 
Mark Sapiro <mark at msapiro.net>        The highway is for gamblers,
San Francisco Bay Area, California    better use your sense - B. Dylan