[Python Glasgow] Consecutive members of a list (Hedieh Ebrahimi)-Glasgow Digest, Vol 16, Issue 5

[Nonso Ibenegbu]

Hi Hedieh,

See if you like this:

myList= [1, 7, 19, 1110]
 
newList = [(myList[x-1], myList[x]) for x in range(1, len(myList))]

Cheers.
Nonso




On 30 Apr 2014, at 11:00, glasgow-request at python.org wrote:

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>   1. consecuetive members of a list (Hedieh Ebrahimi)
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> Message: 1
> Date: Wed, 30 Apr 2014 11:53:20 +0200
> From: Hedieh Ebrahimi <hedieh.ebrahimi at amphos21.com>
> To: Python Edinburgh <glasgow at python.org>
> Subject: [Python Glasgow] consecuetive members of a list
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> 	<CA+ze5C7uKKRDSgd1zbx=99-Ce0wrz4soKL5yZLurBLpVdfAVAQ at mail.gmail.com>
> Content-Type: text/plain; charset="utf-8"
> 
> Hi all,
> 
> Imagine I have a list like this:
> 
> myList= [1, 7, 19, 1110]
> 
> from this list I like to create a list of tuple of ranges like this.
> 
> [(1,7),(7,19),(19,1110)]
> 
> How can I do this in an efficient way ?
> 
> Thanks in advance.
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