[Python Edinburgh] How to do dynamic nesting of loops
Kenny Erasmuson
kennyerasmuson at gmail.com
Tue Nov 18 13:56:08 CET 2014
It sounds like some kind of recursive function may be needed here. However,
it also looks like the 'inner' most function call will then be operating on
a variable number of parameters (e.g. l, m and n in your example, but it
could be l, m, n, k, z, etc). Is that right?
On 18 November 2014 12:53, Tom Dalton <tom.dalton at fanduel.com> wrote:
> Hey Doug,
>
> There are a few ways you could do this, but it would be helpful if you
> could give a little more context on where you get l,m and n from and where
> the limit (10) comes from for each (or how it's determined). Also, what
> does the thing that uses those variables look like? Is it separate function
> calls, or a function that takes a list of arguments, or something else?
>
> Cheers,
>
> Tom
>
> On 18 November 2014 12:08, Douglas Houston <douglasrhouston at googlemail.com
> > wrote:
>
>> Hi all,
>>
>> I'm a bit stuck with this so maybe someone can help me.
>>
>> I'm writing a little program that needs to iterate through several nested
>> 'for' loops. However, the number of loops (and therefore the depth of the
>> nesting) cannot be predetermined.
>>
>> I've read that lots of nested loops are bad form anyway, and that "you
>> should do it with functions instead".
>>
>> However I still can't work out how to set the number dynamically.
>>
>>
>> for ((l=0; l<10; l++)); do
>>
>> for ((m=0; m<10; m++))
>> ;
>> do
>>
>>
>> for (n=0; n<10; n++)); do
>>
>>
>> something
>> that uses l, m and n
>>
>> done
>> done
>> done
>>
>> So this is what it needs to look like if nest_depth=3
>>
>> But how do I write a program that iterates something
>> for nest_depth=4 (which in this case would use l, m, n and o), or any
>> other number (which can't be predicted)?
>>
>> cheers,
>> Doug
>>
>> PS I didn't write this in Python just for speed, but feel free to reply
>> in Python if you want - the practice would be good for me.
>>
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>>
>
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