[C++-sig] Getting a Python type object for a c++ type in wrapper code...

[Nick Rasmussen]

Perhaps something like:

#include <Python.h>
#include <boost/python.hpp>

using namespace boost::python;

struct Foo {

};

struct Bar {
  static object fooType;
};

object Bar::fooType;

BOOST_PYTHON_MODULE(test)
{
  class_<Foo> fooType("Foo");
  Bar::fooType = fooType;
  class_<Bar> barType("Bar");
  barType
    .def_readonly("fooType",&Bar::fooType);
}

-nick


On Tue, 04 Oct 2005, Alex Mohr wrote:

> Hi folks,
> 
> I'm a relative boost.python newbie but I've been doing a ton with it and 
> I'm having a blast.  Thanks for such an awesome package.
> 
> Here's my first newbie question.
> 
> Suppose I have two C++ classes that I'm wrapping -- Foo and Bar.  In the 
> wrapper for Bar, I want there to be an attribute which holds the type 
> Foo.  That is, from python I wan to be able to say:
> 
>  >>> Module.Bar.fooType == Module.Foo
> True
> 
> Something like def_readonly("fooType", <var-which-holds-type-for-Foo>) 
> would be ideal.  I'd also like to be able to do this for python types, 
> like python's float.  Is there a simple way to do this in my 
> Boost.Python code?
> 
> Thanks,
> 
> Alex
> 
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