[C++-sig] implicitly_convertible

[Benjamin Schmeling]

Hi,
I have exposed a bigint class which has no constructor for long_ .
I added an additional constructor by defining .def("__init__", 
make_constructor(bigint_constructor))
This works fine. Now I want to use the implicitly_convertible function 
which expects from the class to have an constructor which takes the 
first argument (in this case a long_)
I used implicitly_convertible<boost::python::long_ ,bigint> but now the 
problem is that the original c++ class has no such constructor, but the 
wrapped class. How can I make it using my new constructor in 
implicitly_convertible?

Benjamin