[C++-sig] Re: call python method from C++
David Abrahams
dave at boost-consulting.com
Fri Jan 30 16:39:05 CET 2004
"Fabrizio" <fabrizio.duhem at free.fr> writes:
> D:\test\boost_python\Release>python test.py
> Traceback (most recent call last):
> File "test.py", line 27, in ?
> eriser.Update(a)
> TypeError: Update() takes exactly 2 arguments (1 given)
>
>
>
> C++ code
>
> class IRenderable
> {
> public:
> virtual ~IRenderable() {}
> virtual void Init() {}
> virtual void Render() {}
> virtual void Update(float dt) {}
> };
>
>
> class IRenderableWrapper : public IRenderable
> {
> public:
> PyObject* self;
>
> IRenderableWrapper(PyObject* self_) : self(self_) {}
>
> void Init()
> {
> return boost::python::call_method<void>(self, "Init");
> }
>
> void DefaultInit()
> {
> return IRenderable::Init();
> }
>
> void Render()
> {
> return boost::python::call_method<void>(self, "Render");
> }
>
> void DefaultRender()
> {
> return IRenderable::Render();
> }
>
> void Update(float dt)
> {
> return boost::python::call_method<void>(self, "Update");
----------------------------------------------------------^
Your problem is right here
You need to pass dt to the Update method.
HTH,
--
Dave Abrahams
Boost Consulting
www.boost-consulting.com
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