[BangPypers] list problem

[Shashwat Anand]

On Thu, Jul 22, 2010 at 7:00 PM, steve <steve at lonetwin.net> wrote:

> Hi,
>
>
> On 07/22/2010 05:02 PM, Anand Balachandran Pillai wrote:
>
>> On Thu, Jul 22, 2010 at 3:21 PM, Vikram<kpguy at rediffmail.com>  wrote:
>>
>>   Suppose you have the following list:
>>>
>>>  >>>  x =[['cat',10],['cat',20],['cat',30],['dog',5],['dog',1],['dog',3]]
>>>
>>>  My problem is that i wish to obtain the following two dictionaries:
>>>  xdictstart = {'cat':10, 'dog':1}
>>>  xdictend = {'cat':30, 'dog':5}
>>>
>>
>>
>>   Any nice way to do the above? Thanks.
>>>
>>>
>>>  Yes. Try this.
>>
>>   x =[['cat',10],['cat',20],['cat',30],['dog',5],['dog',1],['dog',3]]
>>>>>  x.sort()
>>>>>  xdictstart = dict(reversed(x))
>>>>>  xdictend = dict(x)
>>>>>  xdictstart,xdictend
>>>>>
>>>> ({'dog': 1, 'cat': 10}, {'dog': 5, 'cat': 30})
>>
>
> Are you sure that'll work ? Is creating a dict from a sequence guaranteed
> to be executed serially withing the sequence ?


It is nowhere mentioned in Docs IIRC but I have never seen any counter
example.


>
>
> cheers,
> - steve
> --
> random spiel: http://lonetwin.net/
> what i'm stumbling into: http://lonetwin.stumbleupon.com/
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